(1+x^4)+(1+4y^2)=0

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Solution for (1+x^4)+(1+4y^2)=0 equation:


Simplifying
(1 + x4) + (1 + 4y2) = 0

Remove parenthesis around (1 + x4)
1 + x4 + (1 + 4y2) = 0

Remove parenthesis around (1 + 4y2)
1 + x4 + 1 + 4y2 = 0

Reorder the terms:
1 + 1 + x4 + 4y2 = 0

Combine like terms: 1 + 1 = 2
2 + x4 + 4y2 = 0

Solving
2 + x4 + 4y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + x4 + -2 + 4y2 = 0 + -2

Reorder the terms:
2 + -2 + x4 + 4y2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x4 + 4y2 = 0 + -2
x4 + 4y2 = 0 + -2

Combine like terms: 0 + -2 = -2
x4 + 4y2 = -2

Add '-4y2' to each side of the equation.
x4 + 4y2 + -4y2 = -2 + -4y2

Combine like terms: 4y2 + -4y2 = 0
x4 + 0 = -2 + -4y2
x4 = -2 + -4y2

Simplifying
x4 = -2 + -4y2

Reorder the terms:
2 + x4 + 4y2 = -2 + -4y2 + 2 + 4y2

Reorder the terms:
2 + x4 + 4y2 = -2 + 2 + -4y2 + 4y2

Combine like terms: -2 + 2 = 0
2 + x4 + 4y2 = 0 + -4y2 + 4y2
2 + x4 + 4y2 = -4y2 + 4y2

Combine like terms: -4y2 + 4y2 = 0
2 + x4 + 4y2 = 0

The solution to this equation could not be determined.

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